Isn't it strange?

[Richard Meisel]

Just a little humor for these days.
Isn’t it strange? You have $20 and you bet $20 on the 1st Dozen:
W12  L26
Win 12 x20 = 240 
Lose 26 x-20 = -520
Total = -280

What if you bet the $20 on 2 Dozens?
10 on 1st Dozen, 10 on 2nd Dozen
W24  L14
Win 24 x10 = 240
Lose 14 x-20 = -280
Total = -40

And what if you bet $20 on 3 Dozens! What?
1st Dozen = 12 x10 = 120
2nd Dozen = 12 x-5 = -60
3rd Dozen = 12 x-5 = -60
Loss on 0 & 00 = 2 x-20 = -40
Total = -20

You actually lose less betting on all 3 Dozens or all 3 Columns! Now I don’t bet this way and I don’t recommend this bet but I’ve never found on any betting forum or on the internet anyone mentioning this bet, except Saliu mentions it in passing. But isn’t it strange?

[Bigbroben]

Your calculations are wrong.

Please correct. 

First example should give 12x40 since payout is 2:1.  With a total of -40.

Third example has 10 on 1st doz and 5 on both 2 and 3?  If so, results are wrong.

[Taotie]

Isn't it strange, that I just wasted 3 minutes reading and replying to this nonsense.

[Bigbroben]

Isn't it strange, that I just wasted 3 minutes reading and replying to this nonsense.

Not strange: you were probably hoping for an anomaly that would lead to a HG and put you on track to become a filthy-rich king of the world.

Deceptive.

[Richard Meisel]

Your calculations are wrong.

Please correct. 

First example should give 12x40 since payout is 2:1.  With a total of -40.

Third example has 10 on 1st doz and 5 on both 2 and 3?  If so, results are wrong.

Yes, correction: 20 on 1st Dozen
W12  L26
Win 12 x40 = 480 
Lose 26 x-20 = -520
Total = -40

10 on 1st Dozen, 10 on 2nd Dozen
W24  L14
Win 24 x10 = 240
Lose 14 x-20 = -280
Total = -40

10 on 1st Dozen, 5 on 2nd Dozen, 5 on 3rd Dozen
W36  L2
Win on 1st Dozen = 12 x10 = 120
Win on 2nd Dozen = 12 x-5 = -60
Win on 3rd Dozen = 12 x-5 = -60
Loss on 0 & 00 = 2 x-20 = -40
Total = -20

Betting $20 on the 1st Dozen will lose $40 after 38 Spins. Betting $20 ($10 on 1st Dozen and $10 on 2nd Dozen) will lose $40 after 38 Spins. But Betting $20 ($10 on 1st Dozen and $5 on 2nd Dozen and $5 on 3rd Dozen) will only lose $20 after 38 Spins. Bad Bet. Whoever thought of Betting on all 3 Dozens at once or all 3 Columns at once? Saliu mentions it. But, still, isn't it strange? Some of you aren't very nice. It took a long time for me to be a nice guy.

[plolp]

What is strange is that you take a particular case to make it general

[gizmotron2]

What is strange is that you take a particular case to make it general

Been watching your play at R-sim. Very interesting stuff. Do you think you have winning all figured out?

[Moxy]

Isn't it strange, that I just wasted 3 minutes reading and replying to this nonsense.

Meh.  I've seen stranger things.




I'll be here all week.

[plolp]

@ Gizmotron :

maybe not ... My last 21 games are all won by equal weight, in that I am happy.
then i improve this, for now i don't know.

[Richard Meisel]

Isn't it strange, that I just wasted 3 minutes reading and replying to this nonsense.

Isn't it strange?
AMERICAN WHEEL
N   =   log(1 -DC)/log(1 -p)   When DC = 2/3 (66.6%) and   p = 1/38      
log(1 -DC)   =   log(1 -2/3)   =   log(1 - .66666)   =   log(.33334)   =   -0.4771
log(1 -p)   =   log(1 -1/38)   =   log(1 - .02631)   =   log(.97369)   =   -0.0115
N   =   -.47711/-.011579   =   41.2   =   42

EUROPEAN WHEEL
N   =   log(1 -DC)/log(1 -p)   When DC = 2/3 (66.6%) and   p = 1/37      
log(1 -DC)   =   log(1 -2/3)   =   log(1 - .66666)   =   log(.33334)   =   -0.47711
log(1 -p)   =   log(1 -1/37)   =   log(1 - .027027)   =   log(.97297)   =   -0.01189
N   =   -.47711/-.011899   =   40.09   =   40