Kimo Li's Pinwheel events?

[SWEET]

I tried hard to understand PW signature events strategy.
Hope you guys could chips in ideas.

I personally, believe there's a hg in pw, not you win every season, but after a week, mont or year, net profit>net losses.
(Thanks to stringbeanpc's10k spins pw)
say, in previous 9spins,
arranged into 3rows pw.

say , I see an event
x=single dozen.

oox (3rd dz not hit)
oxo (2nd dz)
xoo (1st dx)

or
xoo
oxo
oox.

then that next 9spins repeat exactly is highly not possible.
Thus we may bet single dz.

[SWEET]

Gizmotron and Sensie Kimo Li, had both said, they could turn Double Dozens bet into 50/50 bet, this is very interesting, because we could bet long streak of dd with this progression.
""Gizmotron's: So can I. One way is to see the sleeping dozen and to bet one side of the remaining two dozens with 20 units and the other non sleeping dozen with 10 units. That's a total of 30 units bet. If the dozen with the 20 units hit then I get 30 more units. That's a 50 /50 bet. If the dozen with the 10 units hit I get a net break even as if the bet never happens. I bet 30 units and netted 30 units. If I lose the bet because the sleeping dozen wakes up then I lose 30 units. Once again this is a 50/50 bet. But I'm covering two thirds of the table on each try.  Big deal, whoopty doo. I shared this concept more than ten years ago at Gambler's Glen. I don't like waiting on sleeping dozens anymore."unquote

[SWEET]

I think we could also take, say, 10 or 20 rows of pw, THAT HAS NO all three dz hit, in a row, and regard them as LOSING signature event, and grind bet that event hoping it will produce well balanced bet WITHIN MATH EXPECTATION.

[leoncino74]

I tried hard to understand PW signature events strategy.
Hope you guys could chips in ideas.

I personally, believe there's a hg in pw, not you win every season, but after a week, mont or year, net profit>net losses.
(Thanks to stringbeanpc's10k spins pw)
say, in previous 9spins,
arranged into 3rows pw.

say , I see an event
x=single dozen.

oox (3rd dz not hit)
oxo (2nd dz)
xoo (1st dx)

or
xoo
oxo
oox.

then that next 9spins repeat exactly is highly not possible.
Thus we may bet single dz.

Ciao, puoi aiutarmi a capire come giocare una singola dozzina da questi schemi, grazie

[number25]

@ Sweet  I hope you can crack the PW code.  It will happen...... Just think out side of the box! 

[SWEET]

xoo
oxo
oox
above simply mean
1st dz missing in first three spin,2nd dz in second and 3rd dz in last row.
In my small 3000rows data,
after ...

xoo
oxo
oox
there never a repeat of exact pw in next three rows.
The same for others pattern

xoo
oox
oxo

or...

oox
oxo
xoo

oxo
oox
xoo

or any three different dz missing in any sequence.
There may a near miss..
eg.

xoo
oxo
oox..then
xoo...again.
this pattern give opportunity to bet less spins...(6spins bet)

[SWEET]

I am computer illiterate,
thus simply hope anyone here could research a 100k, or millions spins pw to see how many 3rows pw being repeat or mirrored repeat..
eg
oox
oxo
xoo..then
xoo
oxo
oox

above example of mirrored repeat.

then how the progression to profit?

Any sequence could be an event...
xoo
xoo
oox...

also an event.

oxo
oox
oxo...
also an event.
any two dz missing in sequence also an event.

if we wait for FOUR rows,
then the fourth row REPEAT the first row,
will reduced the risk to bet less spin.

The same for MIRRORED repeat.
(repeat the last row)
eg.
oox
oxo
xoo..last
xoo .. repeat last

[SWEET]

you could simply walk into casino, and sit down and bet straight away without waiting!?
Why and how?!
Simply bey next 9spins,
will not become any choosen event...
say. eg.
oox
oxo
xoo..
will not happen in next 9spins.
This has it own %losses.
but for a chance to hit exactly your chosen event in 9spins,is small.
I dont know the %,maybe some erudite member here could give the %.

we could also bet only 6spins?!
How?
Simply take the last 3spins as a losing 3spins, and bet the remaining 6spins for your chosen spins event.
eg.
xoo, last 3spins.
oxo
oox, as chosen event

[SWEET]

you may also simply wait for 6spins with 2 dz missing,
and bet only the last row!?
thus you only bet 3spins, greatly reduce stakes...

[SWEET]

Any previous 9spins (without zero, and a
"all three dz in 3spins"),
could be an event to bet,
EXCEPT when there ONLY a single dz missing.
eg.
xoo
xoo
xoo
1st dz had missing for 9spins, and MAY missing further for many  more spins!

[SWEET]

we could also bet
DOUBLE DOZEN
with these events.

eg.
xoo(2nd,3rd dz hit )
oxo(1st,3rd)
oox(1st,2nd)
we CANNOT bet the above because we lose
all 9spins if the single dz
hit exactly replace the missing dz.
even if only lose one row , then you lose 3time.
We could only bet when previous two rows have two missing dz sequence.
eg.
xoo
oxo..now bet dd
oox..3rd wont hit.

[SWEET]

According to Gizmotron's,
we could, mathwise,
apart from green zero,

33.33%win +3.
33.33% win 0.
33.33% lose -3.
thus, without green consideration,

in layman's term, there's no edge, but, 'high'-expectation,
that

66% will either win,
+3, or 0,

33% will
losing -3,
thus the FALLACY,
that 66 vs 33.

so how to bet?
in oversimplified eg.
A bet 1
B bet 2
C bet 3unit.

so, you bet dzA wont hit
,you placed 1u, on dzA.

you bet dzC will hit, you placed 3u on dzC.

placed 2u on dzB, to neutrealise
the staking...of 6unit.

if dzA hit
win +2, lose-5
=-3.

if dzC hit.
win+6, lose-3,
profit=3.

if dzB hit,
win +4,lose-4,
profit=0.

thus mathwise,

apart green,
66.66% to win+3
33.33% to lose-3.
is this a fallacy!!???

[mohitomish]

HI,

Please use your brain,  you sit and bet for 9 spin events to not occur right?   How is this different from betting red or betting black to not occur?

your event of 9 spins is equal to a betting event of 1 spin and the probability and the losses will occur accordingly. You will lose to the house edge.

[gizmotron2]

""Gizmotron's: So can I. One way is to see the sleeping dozen and to bet one side of the remaining two dozens with 20 units and the other non sleeping dozen with 10 units. That's a total of 30 units bet. If the dozen with the 20 units hit then I get 30 more units. That's a 50 /50 bet. If the dozen with the 10 units hit I get a net break even as if the bet never happens. I bet 30 units and netted 30 units. If I lose the bet because the sleeping dozen wakes up then I lose 30 units. Once again this is a 50/50 bet. But I'm covering two thirds of the table on each try.  Big deal, whoopty doo. I shared this concept more than ten years ago at Gambler's Glen. I don't like waiting on sleeping dozens anymore."unquote

Still true. I just did a huge upswing & downswing example at R-sim in my latest demonstration of double dozens style.

[SWEET]

Hi Mohi,
9spins event, or pattern,
where
1st sleep for 3spins,
then,
2nd sleep for 3spins,
then,
3rd sleep for 3spins,
thus, pinwheel,

xoo
oxo
oox
pattern,
this pattern, may and will happen, and also may, and will hit back to back.
but the chance it will hit the moment you sit at the table, is small.
you may wait for, say,

xoo
thats 1st had sleep for 3spins, then bet for next 6spins, that 2nd, and 3rd will hit.
or wait for,
xoo,
oxo,
then bet, 3rd will hit, for next 3spins.
This just a game of probabilities, no 100%
grail.

If we use,
Gizmotron's idea of 50/50 to bet in dozen bet, where albeit green,
33% will lose...1
33% will no winlose.
33% will win 1.
then we wait for the matrix to produce two different dz, then bet one on the left with 1u, and the right with two, then parlay the win...
this has no edge, but the chance of hit and run 66 vs 33 (falacy?)