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How to nullify the negative edge (for free)

Started by outsider, Jan 25, 07:27 PM 2021

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0 Members and 3 Guests are viewing this topic.

outsider

as I'm in a good mood for how my method is going here... today i want to teach something very interesting imo.
How to manipulate the bets and the probabilities... to reduce the edge, until it (almost) completely disappears.
I will just do a simple example to let everyone understand.

If i have 6 units and i wanna make 6 new units...  the common way is to bet the 6 units on the red, or black... with a probability of 0.4865.
BUT, there is another way to double your 6 units, with a greater probability...  (0,4892 in this case)
In fact if i bet 3 unit on the first dozen, i can win 6 new units. But if i lose, i still have 3 more units that i can put on 3 triplets. And if i win this shot, i get a total of 12 units!

So in both scenarios we try to double or units but there is a difference.

1) simple chance (black, red, odds, even, manque, passe)       P = 0.4865 (18/37)
2) half budget on the dozen, if i win i doubled my budget! If i lose, i put the second half on 3 triplets to double my initial budget      P = 0.4892 (this number is the probability of winning the first shot + the probability of losing the first shot but winning the second...)

As you can see, same goal with two different probabilities! With the second way we have reduced the casinò edge (from 0.0135 to 0.0108)!!!

Now you can think, this is not a big deal... well, this is just a simple example of how to look things in a different way and open you mind.
Like i said above, It's possibile to manipulate the bets through different combinations that heavily crushes the edge.

This method is designed just to let the gambler play in a fair way, so it doesn't give any concrete advantage... otherwise i wouldn't give it for free just like that! :)
It's stressful for me to type in english so i will end it here... enjoy the gift and let your fantasy go wild. Find your way to  nullify the edge (if you are interested in doing so).



Roulettebeater

Quote from: outsider on Jan 25, 07:27 PM 2021
as I'm in a good mood for how my method is going here... today i want to teach something very interesting imo.
How to manipulate the bets and the probabilities... to reduce the edge, until it (almost) completely disappears.
I will just do a simple example to let everyone understand.

If i have 6 units and i wanna make 6 new units...  the common way is to bet the 6 units on the red, or black... with a probability of 0.4865.
BUT, there is another way to double your 6 units, with a greater probability...  (0,4892 in this case)
In fact if i bet 3 unit on the first dozen, i can win 6 new units. But if i lose, i still have 3 more units that i can put on 3 triplets. And if i win this shot, i get a total of 12 units!

So in both scenarios we try to double or units but there is a difference.

1) simple chance (black, red, odds, even, manque, passe)       P = 0.4865 (18/37)
2) half budget on the dozen, if i win i doubled my budget! If i lose, i put the second half on 3 triplets to double my initial budget      P = 0.4892 (this number is the probability of winning the first shot + the probability of losing the first shot but winning the second...)

As you can see, same goal with two different probabilities! With the second way we have reduced the casinò edge (from 0.0135 to 0.0108)!!!

Now you can think, this is not a big deal... well, this is just a simple example of how to look things in a different way and open you mind.
Like i said above, It's possibile to manipulate the bets through different combinations that heavily crushes the edge.

This method is designed just to let the gambler play in a fair way, so it doesn't give any concrete advantage... otherwise i wouldn't give it for free just like that! :)
It's stressful for me to type in english so i will end it here... enjoy the gift and let your fantasy go wild. Find your way to  nullify the edge (if you are interested in doing so).

By reading the classy  introduction of  your thread i thought you have knocked the roulette and want to share you multimillionaire money making machine but the joy didn’t last long, unfortunately it’s much said but the output is still 0

the content is not different than the usual bullshits we usually read
A dollar won is twice as sweet as as a dollar earned

outsider

Quote from: Roulettebeater on Jan 25, 11:32 PM 2021
By reading the classy  introduction of  your thread i thought you have knocked the roulette and want to share you multimillionaire money making machine but the joy didn’t last long, unfortunately it’s much said but the output is still 0

the content is not different than the usual bullshits we usually read
hahahahahahaha the output is still 0? ...not different than the usual bullshits????? Do you realize what this means? Reducing the casinò edge... i'm sure that this thread is more useful than the 100% of the discussions here in this forum (no offense). THIS is something CONCRETE. I SHOWED how it's possible to do it!!! FACTS!!!
Why i'm saying that this thread is more useful than the 100% of the discussions here?
Because any known method here ends to lose because of the 2.7% tax! And at least i showed (with this simple example) how to lose less!!! FACTS!!! Who wants, can use this technique to play a FAIR game! If this is bullshit for you... you wasted a lot of time here, mate.


plolp


If you conclude this, you have made a miscalculation.
a lower percentage (2.70%) played twice in a row cannot give a higher probability than a single shot played at 1.35%.

Roulettebeater

Quote from: plolp on Jan 26, 12:00 PM 2021
If you conclude this, you have made a miscalculation.
a lower percentage (2.70%) played twice in a row cannot give a higher probability than a single shot played at 1.35%.

Exactlyyyyyyyyy!!!!!!
A dollar won is twice as sweet as as a dollar earned

outsider

Quote from: plolp on Jan 26, 12:00 PM 2021
If you conclude this, you have made a miscalculation.
a lower percentage (2.70%) played twice in a row cannot give a higher probability than a single shot played at 1.35%.
please... read again (carefully what i explained

Roulettebeater

I urgently invite uncle Steve to leave a comment here
A dollar won is twice as sweet as as a dollar earned

plolp


Ousider :

if I play 3 coins on the 0 and if I lose I play 3 more coins on the zero, will I lose more than you do?

outsider

Quote from: plolp on Jan 26, 12:00 PM 2021
If you conclude this, you have made a miscalculation.
a lower percentage (2.70%) played twice in a row cannot give a higher probability than a single shot played at 1.35%.

I told each probabilty above...
normal way to double the capital 0.4865
alternative way to double the capital 0.4892
Is math, and you can not run away from it... test it if you want.

I want to do another example, 2 units to make 1
normal way: you play 2 units on 2 dozens
alternative way: you play 1 units on red, and if you lose, 1 units on 1 dozen
both ways leads to the same result, but the alternative way has a greater chance.
I repeat it's math... try by yourself or give this to a math teacher, an expert... or whoever  can do a clear objective analysis, if you don't trust me. (the numbers that i SHOWED)

Roulettebeater

You are summing two independent probabilities for two different bets !!
I call this an elementary error,  I always warn my pupils from making such errors in maths...
A dollar won is twice as sweet as as a dollar earned

plolp

Outsider :
How many losing possibilities in your first scenario?
In other words, how many times are you going to lose your two bets?
If you have considered all the possibilities you should respond instantly.

I will answer for you.
There are 700 loss scenarios
So why only talk about the positive scenarios?

Roulettebeater

@plolp

Yea, the forum is full of gambler fallacies

Maybe Steve should create a section called „fallacies“ for such threads :thumbsup:
A dollar won is twice as sweet as as a dollar earned

outsider

Quote from: plolp on Jan 27, 04:44 AM 2021
Outsider :
How many losing possibilities in your first scenario?
In other words, how many times are you going to lose your two bets?

700? What this even means?
Look, it's simple.

1 unit on the red  ( p = 0.4865)
if we lose the first bet we play 1 unit on a dozen ( p = 0.3243)
What's the probability to win at least one of those bets?        ----> 0.4865+(1-0.4865*0.3243) = 0.6530
This means that  the probabiliy to lose both bets is:          q = 1 - 0.6530 = 0.347

Instead... if you play 2 units on 2 dozens = the probabilty would be only 24/37= 0,6486

So with this trick we "earned" 0.6530 - 0.6486 = 0.0044 (0.44%)





outsider

Quote from: outsider on Jan 27, 10:40 AM 2021

   ----> 0.4865+(1-0.4865*0.3243) = 0.6530


i'm pretty sure that here, i have teached an unkown formula to the 99,9999% (maybe 100%?) of the users in this forum.

Roulettebeater

Sorry but u didn’t convince me - anyway the house edge is still far away from ur little 0.44%
A dollar won is twice as sweet as as a dollar earned

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