A New Way of Looking at betting 35 numbers

[ScoobyDoo]

Hi Guys,
I hope I can explain this idea well enough so you get the idea.

Lets say the last spin was #27 and the next spin is #14 on the wheel. That is 16 spaces apart.

Now look on the table layout with the same numbers. The #27 & #14 are 23 spaces apart.

The bet: The wheel bet will not be 23 spaces to the next number and the table bet will not be 16 spaces apart.

So you count to the number on the wheel that is 23 spaces past the #14 and leave that number open on the table....Then you look at the table to see what number is 16 spaces from the #14 on the table and leave that number open.

Cover the remaining numbers with one unit each. (This will only work on a European Wheel)

I think it will take a very long time before the spacing on the Wheel and the a table will match.

These above numbers will not match on a european wheel but it works the same way.

Let me know what you think or if you have questions let me know.

Scooby Doo

[chrisbis]

Hi Scoob

I near to getting the jist of your idea.

I've been working on a similar scheme for ages now.

Just wondered if you/we might get more help/discussion
if you show the movements you spoke of,
in a graphical formate on a couple of drawings?

There are blanks in here- look under FELT for table layout,
and ask Victor VLS for Disc/wheel drawings.( Or Kattila has some blanks too)

Disc (with one of my movement marks)
[attachimg=#1]

Felt from the archive is here.
[attachimg=#2]

[weddings]

So we leave 13, 30 blank? Do we count 0 as well in the wheel/table or ignore it.

[ScoobyDoo]

Hi chisbis,

Even if I have e pic of the wheel, I don't know how to put the lines and arrows on it like you did.

Maybe I could ask you kindly to do it for me, at least for one demonstration.

Lets use the numbers 26-14-3

That will give a spin to bet on....

And of course a table layout with the same three numbers.

If you will do that for me, I think I can explain it much better.

Thanks,
Scooby Doo

[ScoobyDoo]

Hi Weddings,

yes, you count the Zero. You will be betting on 35 of the 37 numbers. If you land on Zero, count from the last number up to Zero and that will give you the count you are looking for.

Scooby Doo

[weddings]

always clockwise? how are you doing up till now?

[ScoobyDoo]

Hi Weddings,

I have not tried this with spinning wheels that go in two different directions but my approach would be to put them in two groups and play them serately.

The odds of the wheel and the board being the same number of notches from the last number is highly unlikely.

Scooby Doo

[Twisteruk]

The odds of the wheel and the board being the same number of notches from the last number is highly unlikely.

Scooby Doo

Do you know what those odds are plz Scoob ?

[Mikeo]

I think it will take a very long time before the spacing on the Wheel and the a table will match.

True, but:

If I understand correctly, you are betting that the spacing (23 and 16 from your example) will not repeat, switching wheel spacing to table, and table to wheel.

On the bet, you are leaving one number open based on the wheel, and another number open based on the table. But only one has to hit for you to lose. So they are not a combined condition, but separate conditions.

Again using your example, 23 spaces and 16 spaces, the bet cannot be that you win unless 23 AND 16 repeat, but that you win unless 23 OR 16 repeat, much lower odds.

While it's true that both will rarely repeat, only one has to repeat for you to lose.

Am I interpreting it correctly?

[ScoobyDoo]

Hi Mikeo,

What we would be betting is that the wheel spacing will not be the same as the table spacing and the reverse would also be true.

It's true that if one of those bets came up as the same as the opposite, you would lose that bet and win the other. (Lose 35 units....Win 1 unit)

I think that losing one or the other of those bets would not happen within several hundred, if not thousands of spins so an occasional loss would mean nothing.  Exact odds I am not sure of.

Scooby Doo

[chrisbis]

Any Use Scooby?
[attachimg=#]

[ScoobyDoo]

Hi Guys,

Ok, if you look at the wheel and board illistrations above, Count the spaces from #27 continueing until you get up to and including #14. Do not count #27. On the wheel, that will add up to 14 spaces and on the board, it adds up to 23 spaces.

So Our next move is to count 23 spaces from #14 on the wheel and 14 spaces on the board. Whatever those two numbers are, we will leave open and bet one unit on all of the other numbers.

Note: Unless the Zero is within your spacing count, DO NOT include it in your space count on the board.

Scooby Doo

[ScoobyDoo]

Hey Chrisbis,

Thanks for your help putting the wheel and board imagines in your post. You only made one mistake. Unless the Zero is part of your spacing count, you do not include it.

Scooby Doo

[Mikeo]

It's true that if one of those bets came up as the same as the opposite, you would lose that bet and win the other. (Lose 35 units....Win 1 unit)

Hi Scooby,

Maybe I'm still missing something, but you refer to 2 bets. I only see one bet, shown here.

[attachthumb=#1]

So for the next bet in the example, you leave 13 and 30 open, and cover the other 35 numbers.
If 13 or 30 hit, you lose 35. There is no other bet to win.

Is this not correct?

I think that losing one or the other of those bets would not happen within several hundred, if not thousands of spins so an occasional loss would mean nothing.  Exact odds I am not sure of.

If this proves to be true, it would definitely be a winner.

Thanks
Michael

[chrisbis]

Hi Weddings,

yes, you count the Zero. You will be betting on 35 of the 37 numbers. If you land on Zero, count from the last number up to Zero and that will give you the count you are looking for.

Scooby Doo

Very confused now.

One minute U say U count zero, then U tell me not to count zero.

If U are playing a strategy game of flat betting multiple numbers in order to secure an advantage by saying the ball WILL NOT LAND at a certain point, then surely U must count Zero, as Its just a number like any other, and has the same chance of the ball landing on it in any given spin.


I did not understand Ur request for a drawing because U gave me three numbers (26- 14 -3) without instructing me where the movement had come from, from which direction the movement was, or the rotation of the wheel, which as |U know in live wheels, is alternating every spin.

Give me some more numbers & instructs, and I'll do another drawing for U Scoob.

I'm liking the Topic tho!! Nice one.