An idea for a MATRIX bet.

[flukey luke]

Here is an idea I had regarding the matrix.

1 = 1A. (The 1 represents the first dozen and the A represents the first column.)
2 = 1B. (The 1 represents the first dozen and the B represents the second column.)
3 = 1C. (The 1 represents the first dozen and the C represents the third column.)
4 = 1A.
5 = 1B.
6 = 1C.
7 = 1A.
8 = 1B.
9 = 1C.
10 = 1A.
11 = 1B.
12 = 1C.
13 = 2A. (The 2 represents the second dozen and the A represents the first column.)
14 = 2B. (The 2 represents the second dozen and the B represents the second column.)
15 = 2C. (The 2 represents the second dozen and the C represents the third column.)
16 = 2A.
17 = 2B.
18 = 2C.
19 = 2A.
20 = 2B.
21 = 2C.
22 = 2A.
23 = 2B.
24 = 2C.
25 = 3A. (The 3 represents the third dozen and the A represents the first column.)
26 = 3B. (The 3 represents the third dozen and the B represents the second column.)
27 = 3C. (The 3 represents the third dozen and the C represents the third column.)
28 = 3A.
29 = 3B.
30 = 3C.
31 = 3A.
32 = 3B.
33 = 3C.
34 = 3A.
35 = 3B.
36 = 3C.

Here are some numbers I recorded from my session at the casino earlier this afternoon.

25
2
2
6
16
16
22
6
16
9
15
10
21
35
13
6
7
25
25
35
15
11
7
10
23
11
15
32
32
1
14
32
7
12
11
19
19
3
23
24
6
3
17
3
18
7
32
35

Now using my chart from above, let's feed them into a matrix and see what happens.

3A  1B  1B  1C
2A  2A  2A  1C
2A  1C  2C  1A
2C  3B  2A  1C
1A  3A  3A  3B
2C  1B  1A  1A
2B  1B  2C  3B
3B  1A  2B  3B
1A  1C  1B  2A
2A  1C  2B  2C
1C  1C  2B  1C
2C  1A  3B  3B

So there you have it.

If you go to the second line in the matrix and read across, you will see 2A 2A 2A.
Now here is where I would look for the 2A to break.
That would require me to play the following numbers.
2/3, 5/6, 8/9, 11/12, 26/27, 29/30, 32/33, 35/36. That comes to 8 splits.
You will find all the possible bets for this method will come to 8 splits.

That bet would have won because after 2A 2A 2A, you will see that 1C arrived.

The only other bet in the matrix was in the second column going down vertical.
You will see 1C 1C 1C.
I would look for the 1C to break.
That would require me to play the following numbers.
13/14, 16/17, 19/20, 22/23, 25/26, 28/29, 31/32, 34/35. Once again, only 8 splits.

That bet would also have won because after 1C 1C 1C, you will see that 1A arrived.

I like this bet because the outlay is less than playing two dozens. You could use a longer progression if you wanted. Also you are looking for a combination of a dozen AND a column together to keep repeating.

I would play more or less the same way some of you guys are playing the other matrix ideas.
Play after the third repeat (as shown in the examples above) and if it does not win, wait for another three to appear and try again. Because you are only betting 8 splits, you should be able to stretch some kind of betting progression to allow this to be almost unbreakable.

I will spend a few days doing some testing and come back with the results.

cheers.

[Twisteruk]

Superb 


I will test tonight and report back 

[chrisbis]

Looks interesting John.

Thanx for this. 

[flukey luke]

No problems guys.

I agree with what you were saying Twister, I just had the figure of 3 fixed in my head. I went back and had another look at the matrix and just waiting for 2 to repeat and betting opposite is throwing up nice results.

Oh well, time to get the old testing gear back out.  

[Twisteruk]

No problems guys.

I agree with what you were saying Twister, I just had the figure of 3 fixed in my head. I went back and had another look at the matrix and just waiting for 2 to repeat and betting opposite is throwing up nice results.

Oh well, time to get the old testing gear back out.  

Yep I agree 100%
We can test this and see what gives !

Then decide on rules of play once we have some hard data to disect 

[jon86]

Yep I agree 100%
We can test this and see what gives !

Then decide on rules of play once we have some hard data to disect 

[ZigZag]

LOOKS GREAT 

ophis type tracker would be great for this because of the shot time you have to place 8 splits, especialy if your on slingshot 

[Twisteruk]

LOOKS GREAT 

ophis type tracker would be great for this because of the shot time you have to place 8 splits, especialy if your on slingshot 

I must admit that was my 1st thought too

A tracker is prob gonna be needed for this

[warrior]

Some bets you could bet four corners instead of 8 splits.

[Twisteruk]

Here is an idea I had regarding the matrix.

1 = 1A. (The 1 represents the first dozen and the A represents the first column.)
2 = 1B. (The 1 represents the first dozen and the B represents the second column.)
3 = 1C. (The 1 represents the first dozen and the C represents the third column.)
4 = 1A.
5 = 1B.
6 = 1C.
7 = 1A.
8 = 1B.
9 = 1C.
10 = 1A.
11 = 1B.
12 = 1C.
13 = 2A. (The 2 represents the second dozen and the A represents the first column.)
14 = 2B. (The 2 represents the second dozen and the B represents the second column.)
15 = 2C. (The 2 represents the second dozen and the C represents the third column.)
16 = 2A.
17 = 2B.
18 = 2C.
19 = 2A.
20 = 2B.
21 = 2C.
22 = 2A.
23 = 2B.
24 = 2C.
25 = 3A. (The 3 represents the third dozen and the A represents the first column.)
26 = 3B. (The 3 represents the third dozen and the B represents the second column.)
27 = 3C. (The 3 represents the third dozen and the C represents the third column.)
28 = 3A.
29 = 3B.
30 = 3C.
31 = 3A.
32 = 3B.
33 = 3C.
34 = 3A.
35 = 3B.
36 = 3C.

Here are some numbers I recorded from my session at the casino earlier this afternoon.

25
2
2
6
16
16
22
6
16
9
15
10
21
35
13
6
7
25
25
35
15
11
7
10
23
11
15
32
32
1
14
32
7
12
11
19
19
3
23
24
6
3
17
3
18
7
32
35

Now using my chart from above, let's feed them into a matrix and see what happens.

3A  1B  1B  1C
2A  2A  2A  1C
2A  1C  2C  1A
2C  3B  2A  1C
1A  3A  3A  3B
2C  1B  1A  1A
2B  1B  2C  3B
3B  1A  2B  3B
1A  1C  1B  2A
2A  1C  2B  2C
1C  1C  2B  1C
2C  1A  3B  3B

So there you have it.

If you go to the second line in the matrix and read across, you will see 2A 2A 2A.
Now here is where I would look for the 2A to break.
That would require me to play the following numbers.
2/3, 5/6, 8/9, 11/12, 26/27, 29/30, 32/33, 35/36. That comes to 8 splits.
You will find all the possible bets for this method will come to 8 splits.

That bet would have won because after 2A 2A 2A, you will see that 1C arrived.

The only other bet in the matrix was in the second column going down vertical.
You will see 1C 1C 1C.
I would look for the 1C to break.
That would require me to play the following numbers.
13/14, 16/17, 19/20, 22/23, 25/26, 28/29, 31/32, 34/35. Once again, only 8 splits.

That bet would also have won because after 1C 1C 1C, you will see that 1A arrived.

I like this bet because the outlay is less than playing two dozens. You could use a longer progression if you wanted. Also you are looking for a combination of a dozen AND a column together to keep repeating.

I would play more or less the same way some of you guys are playing the other matrix ideas.
Play after the third repeat (as shown in the examples above) and if it does not win, wait for another three to appear and try again. Because you are only betting 8 splits, you should be able to stretch some kind of betting progression to allow this to be almost unbreakable.

I will spend a few days doing some testing and come back with the results.

cheers.

Ok just finished my chores and come back to this. I've re read it and I've a question,


I need to understand the bit I've highlighted Flukey


Does it win ?

To me it loses. Maybe I've misunderstood.

Maybe you could clarifiy before I start testin in case I've got it wrong



Cheers

[Maui13]

I LIKE!!! 

[Maui13]

Ok just finished my chores and come back to this. I've re read it and I've a question,


I need to understand the bit I've highlighted Flukey


Does it win ?

To me it losses. Maybe I've misunderstood.

Maybe you could clarifiy before I start testin in case I've got it wrong



Cheers

I think what he meant....it's very similar to the MV5...

2A 2A 2A play against another 2A so you would be playing 1 & 3 and B & C

Am I correct in saying this Fluke?

[Twisteruk]

I think what he meant....it's very similar to the MV5...

2A 2A 2A play against another 2A so you would be playing 1 & 3 and B & C

Am I correct in saying this Fluke?

Well he does say 8 splits, which is 16 numbers. Lets wait for clarification 

[Maui13]

I think something like this...

[Twisteruk]

But 1A is 1 4 7 10 which is UNcovered