Lotto - RNF - Basics

[winkel]

Because most wonÃ,´t know my good I start from the beginning!

The difference between Lotto and Roulette is that 1 "spin" gives us always 6 "different" numbers.

There will be no double like 6 and 6 or even a triple in one draw of six. We try to make an opportunity of that.

But still we count this way:

we have 49 diffrent numbers.
after the first ball we will have
48 unhit and 1 hit
after the second ball we will have
47 unhit and 2 hit
...
after the sixth ball we will have
43 unhit and 6 hit

there will be no double hits!

1/1/2000: 13     32     33     8     43     1

this draw will give us:
      1   
   48   6   0
         
0   F0   F1   F>1
1   48   1   0
2   47   2   0
3   46   3   0
4   45   4   0
5   44   5   0
6   43   6   0

[winkel]

IÃ,´m fighting with copying the Excel-sheet. I will find a way.

So we start to make a statistic like shown above.

now we book our second draw
5/1/2000: 20     31     26     16     6     38

      1   
   48   12   0
         
0   F0   F1   F>1
1   48   1   0
2   47   2   0
3   46   3   0
4   45   4   0
5   44   5   0
6   43   6   0
7   42   7   0
8   41   8   0
9   40   9   0
10   39   10   0
11   38   11   0
12   37   12   0


as we see, there had been a repeater possible, but none came up.

additional we open a second count-sheet which starts a new statistic starting with the second draw.

this will show (and it will ever) the same as the first 6 balls of the first spin
   2   
48   6   0
      
F0   F1   F>1
48   1   0
47   2   0
46   3   0
45   4   0
44   5   0
43   6   0

[winkel]

This is a pciture of the summary sheet.

I translated the R or unhit to F0
N the once hit to F1
and all Favourites to F>1

[winkel]

pls give me the third draw

[mogwai]

Here it is. . .

8/1/2000: 49     43     14     41     7     11

[winkel]

So we will add these new 6 numbers to our 1st and 2nd statistic and we will open a third as well.

but what do we expect?

We know that the so called Law of third appears in every game that is bound to random factors.

So we expect that after 49 balls 2/3rd of the 49 numbers will have appeared.
This means 32 numbers and 2/3rd of them will have appeard more than once.

so we expect a combination near to F0=17 F1=19 F>1=13

but till now the summary sheet of our first 3 draws.
as we see we have our first repeater.

[winkel]

@mogwai

pls give the next draw.

But I will proceed tomorrow to give people chance to understand and ask questions.

br
winkel

[mogwai]

No problem. . .  :)

12/1/2000:  29  2     40     19     48     15

[winkel]

There seem to be no questions.

This is our summary-sheet after 4 draws

[winkel]

As you see some counts are marked, I will explain that later.

@mogwai

pls give me now the next 4 draws

br
winkel

[mogwai]

15/1/2000:     10     29     19     43     30     26

19/1/2000:    42     21     8     30     36     13

22/1/2000:     12     3     41     22     35     38

26/1/2000:     8     28     22     6     43     42

:)

[winkel]

Thx Mogwai

here is the summary after 8 draws

[winkel]

As I said before this also reacts like the Law of Third

After 8 draws we should be at 18 or 17 sleeping numbers

like at Roulette after 2/3 of the trot of 37 at spin 25 we should have half numbers sleeping (18/19)

here with 49 numbers 2/3 of trot is 32 balls with 24/25 numbers sleeping

[Akiraa]

Hi Winkel - great thread - so how many previous draws do we need before getting numbers to pick?

[winkel]

Hi Akiraa,

as there were no questions I finished the basic-thread.

next will be number-selection

br
winkel